SOLUTION: Solve the following equations: 1.) X= (2/x+1) 2.) x+3 =(28/x) 3.) (3/x+1)=sq. root of (x+2)

Algebra ->  Systems-of-equations -> SOLUTION: Solve the following equations: 1.) X= (2/x+1) 2.) x+3 =(28/x) 3.) (3/x+1)=sq. root of (x+2)      Log On


   

Question 1097197: Solve the following equations:
1.) X= (2/x+1)
2.) x+3 =(28/x)
3.) (3/x+1)=sq. root of (x+2)
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
x=(2/(x+1))
x(x+1)=2
x^2+x-2=0
(x+2)(x-1)=0
x=-2, 1
check in original
-2=2/(-1), checks
1=2/2, checks.
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x+3=(28/x)
x^2+3x=28
x^2+3x-28=0
(x+7)(x-4)=0
x=4, -7
checks
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3/(x+1)=sqrt(x+2)
9/(x^2+2x+1)=x+2
9=x^3+2x^2+2x^2+4x+x+2
0=x^3+4x^2+5x-7
numerically, this is x=0.79, which when substituted has 1.675=1.67, same given rounding.
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2Cx%5E3%2B4x%5E2%2B5x-7%29