SOLUTION: find two consecutive odd integers such that five times the first equals twelve more than three times th second

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Question 1097017: find two consecutive odd integers such that five times the first equals twelve more than three times th second
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let the consecutive odd integers be
+n+ and +n%2B2+
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given:
+5n+=+3%2A%28+n+%2B+2+%29+%2B+12+
+5n+=+3n+%2B+6+%2B+12+
+2n+=+18+
+n+=+9+
and
+n%2B2+=+11+
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The consecutive odd integers are 9 and 11
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check:
+5%2A9+=+3%2A11+%2B+12+
+45+=+33+%2B+12+
+45+=+45+
OK