SOLUTION: Ben was in charge of ordering 35 pizzas for the office party. He ordered three types of pizza: cheese, pepperoni and supreme. The cheese cost $6, pepperoni $9 and supreme $12. He s

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Ben was in charge of ordering 35 pizzas for the office party. He ordered three types of pizza: cheese, pepperoni and supreme. The cheese cost $6, pepperoni $9 and supreme $12. He s      Log On

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Question 1096927: Ben was in charge of ordering 35 pizzas for the office party. He ordered three types of pizza: cheese, pepperoni and supreme. The cheese cost $6, pepperoni $9 and supreme $12. He spent exactly twice as much on the pepperoni as he did on the cheese pizzas. If been spent a total of $300, how many pizzas of each type did he buy?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = number of cheese bought
Let +b+ = number of pepperoni bought
Let +c+ = number of supreme bought
------------------------------------------
(1) +a+%2B+b+%2B+c+=+35+
(2) +6a+%2B+9b+%2B+12c+=+300+
(3) +9b+=+2%2A%28+6a+%29+
-----------------------------
Multiply both sides of (1) by +12+
and subtract (2) from (1)
(1) +12a+%2B+12b+%2B+12c+=+420+
(2) +-6a+-+9b+-+12c+=+-300+
-------------------------------
+6a+%2B+3b++=+120+
+2a+%2B+b+=+40+
and
(3) +9b+=+12a+
(3) +b+=+%28+4%2F3+%29%2Aa+
-------------------------
Using substitution:
+2a+%2B+%284%2F3%29%2Aa+=+40+
+%2810%2F3%29%2Aa+=+40+
+a+=+%283%2F10%29%2A40+
+a+=+12+
and
+2a+%2B+b+=+40+
+24+%2B+b+=+40+
+b+=+16+
and
(1) +a+%2B+b+%2B+c+=+35+
(1) +12+%2B+16+%2B+c+=+35+
(1) +c+=+35+-+28+
(1) +c+=+7+
-----------------------------
12 cheese
16 pepperoni
7 supreme
-----------------
check:
(2) +6a+%2B+9b+%2B+12c+=+300+
(2) +6%2A12+%2B+9%2A16+%2B+12%2A7+=+300+
(2) +72+%2B+144+%2B+84+=+300+
(2) +300+=+300+
OK