Looks like you're right. Whether by regular
long divsion:
x+ 2
x+9)x²+11x+21
x²+ 9x
2x+21
2z+18
3
or by the shorter synthetic division:
-9|1 11 21
| -9 -18
1 2 3
the remainder is 3. In order for it to be a factor,
the remainder would have to be 0, not something else,
like, for instance, 3.
Edwin