SOLUTION: Rahim averaged 70 in his first m number of exams. After taking n more exams, he had an overall averaged of 75. In terms of m & n, his averaged for the last n exams was

Algebra ->  Average -> SOLUTION: Rahim averaged 70 in his first m number of exams. After taking n more exams, he had an overall averaged of 75. In terms of m & n, his averaged for the last n exams was       Log On


   

Question 1096800: Rahim averaged 70 in his first m number of exams. After taking n more exams, he had an overall averaged of 75. In terms of m & n, his averaged for the last n exams was
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Rahim averaged 70 in his first m number of exams.
After taking n more exams, he had an overall averaged of 75.
In terms of m & n, his averaged for the last n exams was.
:
let a = the average of the n exams
%28%2870m%2Ban%29%29%2F%28%28m%2Bn%29%29 = 75
multiply both sides aby (m+n)
70m + an = 75(m+n)
70m + an = 75m + 75n
solve for a
an = 75m - 70m + 75n
an = 5m + 75n
a = %28%285m%2B75n%29%29%2Fn is the average for the last n exams