SOLUTION: 4x2 + 4y2 + 16x + 24y + 31 = 0 Find the center and radius of the circle. Thanks! :)

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Question 1096705: 4x2 + 4y2 + 16x + 24y + 31 = 0
Find the center and radius of the circle. Thanks! :)

Found 2 solutions by Alan3354, MathTherapy:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
4x2 + 4y2 + 16x + 24y + 31 = 0
4x^2 + 16x + 4y^2 + 24y = -31
Complete the squares for x & y

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
4x2 + 4y2 + 16x + 24y + 31 = 0
Find the center and radius of the circle. Thanks! :)
4x%5E2+%2B+4y%5E2+%2B+16x+%2B+24y+%2B+31+=+0
4x%5E2+%2B+16x+%2B+4y%5E2+%2B+24y+=+-+31
4%28x%5E2+%2B+4x+%2B+y%5E2+%2B+6y%29+=+4%28-+31%2F4%29 ------- Factoring out a GCF, 4, to get leading coefficients of 1
x%5E2+%2B+4x+%2B+y%5E2+%2B+6y+=+-+31%2F4
Now, complete the square on x and y.
You will work towards getting the equation of the CIRCLE, which is in the form: %28x+-+h%29%5E2+%2B+%28y+-+k%29%5E2+=+r%5E2, where:
%22%28h%2C+k%29%22 = Coordinates of CENTER of circle
r = Radius of the circle