SOLUTION: find a polynomial p with integer coefficients such that 5^2/3 is a zero of p. p(x)=

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Question 1096547: find a polynomial p with integer coefficients such that 5^2/3 is a zero of p.
p(x)=
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52775) About Me  (Show Source):
You can put this solution on YOUR website!
.
For example, this polynomial (binomial)  p(x) = 3x - 5^2.


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Hey, if you want to write   5%5E2%2F3,  write   (5^2)/3   in your post.

If you want to write   5%5E%282%2F3%29,  write   5^(2/3)   in your post.


In other words, use PARENTHESES systematically and properly to make your formulas unambiguous when you post them to this forum.


It is THE RULE and IMPERATIVE REQUIREMENT in this forum.


If you neglect it, your formulas ALWAYS will be ambiguous and unreadable.



Answer by greenestamps(13198) About Me  (Show Source):
You can put this solution on YOUR website!

If you really mean that a root is 5%5E2%2F3, then tutor ikleyn's answer is right.

x-5%5E2%2F3+=+0
3x-5%5E2+=+0, or 3x-25+=+0
which would give you the polynomial
p%28x%29+=+3x-25

My guess is that you really wanted a root to be 5%5E%282%2F3%29

x-5%5E%282%2F3%29+=+0
x+=+5%5E%282%2F3%29
x%5E3+=+5%5E2
x%5E3+=+25
which would give you the polynomial
p%28x%29+=+x%5E3-25