SOLUTION: At the city museum, child admission is $5.90 and adult admission is $9.70 . On Wednesday, twice as many adult tickets as child tickets were sold, for a total sales of $784

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: At the city museum, child admission is $5.90 and adult admission is $9.70 . On Wednesday, twice as many adult tickets as child tickets were sold, for a total sales of $784      Log On


   

Question 1096472: At the city museum, child admission is
$5.90
and adult admission is
$9.70
. On Wednesday, twice as many adult tickets as child tickets were sold, for a total sales of
$784.30
. How many child tickets were sold that day?
Answer by greenestamps(13195) About Me  (Show Source):
You can put this solution on YOUR website!

Since the number of adult tickets was twice the number of child tickets, make a "packet" of two adult tickets and 1 child ticket. The cost of each of those packets is
2%289.70%29%2B5.90+=+19.40%2B5.90+=+25.30

Now divide the total ticket sales by the cost of one of these packets, to find how many packets were sold:
784.30%2F25.30+=+31

31 of the packets were sold; that means 62 adult tickets and 31 child tickets.

Answer: 31 child tickets were sold.