SOLUTION: Suppose the height h of an object thrown straight upward from the ground is given by h = 44.1t - 4.9t^2, where h is in meters and t is the elapsed time in seconds. After how many s

Algebra ->  Functions -> SOLUTION: Suppose the height h of an object thrown straight upward from the ground is given by h = 44.1t - 4.9t^2, where h is in meters and t is the elapsed time in seconds. After how many s      Log On


   

Question 1096358: Suppose the height h of an object thrown straight upward from the ground is given by h = 44.1t - 4.9t^2, where h is in meters and t is the elapsed time in seconds. After how many seconds does the object strike the ground?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
When the object hits the ground,
+h+=+0+
+44.1t+-+4.9t%5E2+=+0+
+t%2A%28+44.1+-+4.9t+%29+=+0+
Note that +t=0+ gives you +h=0+
at the instant object is released
Use the other solution:
+44.1+-+4.9t+=+0+
+4.9t+=+44.1+
+t+=+9+
In 9 sec the object hits the ground