SOLUTION: Find the consecutive odd integers such that the sum of the smallest number and middle number is 27 less than 3 times the largest number.

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Question 1096189: Find the consecutive odd integers such that the sum of the smallest number and middle number is 27 less than 3 times the largest number.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Assumingthreeintegers

n%2B%28n%2B2%29=3%28n%2B4%29-27
-
2n%2B2=3n%2B12-27

2=n%2B12-27

2-12%2B27=n

27-10=n

n=17-----------------The integers are 17, 19, 21.







------mistaken---------------------------------
2=n%2B12-27
n=2-12%2B27
n=-17
The integers: -17, -15, -13

Answer by ikleyn(52800) About Me  (Show Source):
You can put this solution on YOUR website!
.
The correct answer is: The integers are 17, 19, 21. 

Assuming three integers


n+(n+2) = 3(n+4)-27


2n + 2 = 3n + 12 - 27

2 = n + 12 - 27

n = 2-12+27

n = 17


The integers  are   17, 19, 21.