SOLUTION: x varies jointly with "b" and the square of "c". If x = 270 when b = 6 and c = 3, find x when b = 10 and c = 4.

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: x varies jointly with "b" and the square of "c". If x = 270 when b = 6 and c = 3, find x when b = 10 and c = 4.      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1096161: x varies jointly with "b" and the square of "c". If x = 270 when b = 6 and c = 3, find x when b = 10 and c = 4.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
x varies jointly with "b" and the square of "c".
x+=+b%2Ac%5E2
If x = 270 when b = 6 and c = 3,
270+=+K+%2A+6+%2A+3%5E2find k
270 = 54k
k = 270/54
k = 5
therefore the equation is
x+=+5b%2Ac%5E2
find x when b = 10 and c = 4.
x = 5*10*4^2
x = 800