Question 1096031: The length of a rectangle is five inches more than four times its width. If the perimeter of the rectangle is 90 inches, find its dimensions Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website! L = 4W+5
2L + 2W = 90
2(4W+5) + 2W = 90
8W + 10 + 2W = 90
10W + 10 = 90
10W = 80
W = 8 this is the width.
L = 4W+5 = 4(8)+5 = 37
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Check:
2L + 2W = 90
2(37) + 2(8) = 90
74 + 16 = 90 Correct