Question 1095995: There are reports of 8.1 cases of typhoid fever per week, on average, in United States. Assuming that the report follows a Poisson distribution, find the probability that there will be between 2 and 4 inclusive cases in the next week.
So far, I've tried finding the P(4) and P(2), which I found were 0.054443 and 0.009957, respectively. Then I subtracted, P(4) -P(2) and got 0.044486. Am I doing this right?
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! Poisson is discrete, so one needs P(2), P(3), and P(4)
e^(-8.1)*8.1^2/2!=0.001
e^(-8.1)*8.1^3/6=0.027
e^(-8.1)*8.1*4/24=0.054
This equals 0.082
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