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Question 1095959: The sum of two integers is 438, and the larger number is 14 more than 7 times the smaller number. Find the two integers
Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! The sum of two integers is 438,
a + b = 438
and the larger number is 14 more than 7 times the smaller number.
a = 7b + 14
In the first equation, replace a with (7b+14)
(7b+14) + b = 438
8b = 438 - 14
8b = 424
b = 424/8
b = 53
:
Find a
a =7(53) + 14
a = 371 + 14
a = 385
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Check this, the sum: 385 + 53 = 438
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