SOLUTION: Joey and Mark go on vacation and travel in opposite directions. Joey leaves the house at 8 AM and averages 35 mph. Mark leaves at 9 AM and averages 40 mph. A what time will they b
Algebra ->
Length-and-distance
-> SOLUTION: Joey and Mark go on vacation and travel in opposite directions. Joey leaves the house at 8 AM and averages 35 mph. Mark leaves at 9 AM and averages 40 mph. A what time will they b
Log On
Question 1095822: Joey and Mark go on vacation and travel in opposite directions. Joey leaves the house at 8 AM and averages 35 mph. Mark leaves at 9 AM and averages 40 mph. A what time will they be 225 miles apart? Found 3 solutions by Alan3354, richwmiller, MathTherapy:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Joey and Mark go on vacation and travel in opposite directions. Joey leaves the house at 8 AM and averages 35 mph. Mark leaves at 9 AM and averages 40 mph. A what time will they be 225 miles apart?
----------
Hint: going in opposite directions, the speeds are added.
You can put this solution on YOUR website! 40m+35*(m+1)=225
40m+35m+35=225
75m=190
m=190/75
m=2.53333333333
m=2 hours 32 minutes
They will be 225 miles apart at 12:32 pm
check
2.53333333333*40+3.53333333333*35=225
ok
You can put this solution on YOUR website!
Joey and Mark go on vacation and travel in opposite directions. Joey leaves the house at 8 AM and averages 35 mph. Mark leaves at 9 AM and averages 40 mph. A what time will they be 225 miles apart?
