You can put this solution on YOUR website! a:b = c:d —> a/b = c/d —> a/b = k (and also c/d = k)
a/b = k —> a=bk —> ma = mbk
c/d = k —> c =dk —> nc = ndk
Now take
and substitute for 'ma' and 'nc':
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Ans:
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Check: Say a/b = c/d = 3
now if a=6, b=2 and c=21, d=7 we get (m & n can be left symbolic):