SOLUTION: Hi, I'm tried to solve these problems but I'm having trouble:
1) If loga(x) = 0.6 and loga(y) = 0.2, evaluate loga(x^2/square root y) - I don't know how to express loga(y) as a
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-> SOLUTION: Hi, I'm tried to solve these problems but I'm having trouble:
1) If loga(x) = 0.6 and loga(y) = 0.2, evaluate loga(x^2/square root y) - I don't know how to express loga(y) as a
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Question 1095566: Hi, I'm tried to solve these problems but I'm having trouble:
1) If loga(x) = 0.6 and loga(y) = 0.2, evaluate loga(x^2/square root y) - I don't know how to express loga(y) as a square root.
What I have tried: loga(x) + loga(x) - loga(square root y)
2) loge(x) - 3 = loge(square root x).....when x>0
Thankyou in advance. Found 2 solutions by josgarithmetic, MathTherapy:Answer by josgarithmetic(39620) (Show Source):
You can put this solution on YOUR website! to help with question #1.
(In case the display does not work well, that is x to the one-half power.)
You can put this solution on YOUR website! Hi, I'm tried to solve these problems but I'm having trouble:
1) If loga(x) = 0.6 and loga(y) = 0.2, evaluate loga(x^2/square root y) - I don't know how to express loga(y) as a square root.
What I have tried: loga(x) + loga(x) - loga(square root y)
2) loge(x) - 3 = loge(square root x).....when x>0
Thankyou in advance.
1) ------ Substituting
2) ----------- Converting to EXPONENTIAL form
---- Squaring both sides