SOLUTION: Hi, I'm tried to solve these problems but I'm having trouble: 1) If loga(x) = 0.6 and loga(y) = 0.2, evaluate loga(x^2/square root y) - I don't know how to express loga(y) as a

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Hi, I'm tried to solve these problems but I'm having trouble: 1) If loga(x) = 0.6 and loga(y) = 0.2, evaluate loga(x^2/square root y) - I don't know how to express loga(y) as a       Log On


   



Question 1095566: Hi, I'm tried to solve these problems but I'm having trouble:
1) If loga(x) = 0.6 and loga(y) = 0.2, evaluate loga(x^2/square root y) - I don't know how to express loga(y) as a square root.
What I have tried: loga(x) + loga(x) - loga(square root y)
2) loge(x) - 3 = loge(square root x).....when x>0
Thankyou in advance.

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%28x%29=x%5E%281%2F2%29 to help with question #1.
(In case the display does not work well, that is x to the one-half power.)

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, I'm tried to solve these problems but I'm having trouble:
1) If loga(x) = 0.6 and loga(y) = 0.2, evaluate loga(x^2/square root y) - I don't know how to express loga(y) as a square root.
What I have tried: loga(x) + loga(x) - loga(square root y)
2) loge(x) - 3 = loge(square root x).....when x>0
Thankyou in advance.
1)   matrix%281%2C3%2C+log+%28a%2C+%28x%29%29%2C+%22=%22%2C+0.6%29            matrix%281%2C3%2C+log+%28a%2C+%28y%29%29%2C+%22=%22%2C+0.2%29

     log+%28a%2C++x%5E2%2Fsqrt%28y%29%29
     log+%28a%2C+%28x%5E2%29%29+-+log+%28a%2C+%28sqrt%28y%29%29%29
      
     2+%2A+log+%28a%2C+%28x%29%29+-+%281%2F2%29+%2A+log+%28a%2C+%28y%29%29
     2%280.6%29+-+%281%2F2%29%280.2%29 ------ Substituting  
     highlight_green%28matrix%281%2C3%2C+1.2+-+0.1%2C+%22=%22%2C+highlight%281.1%29%29%29

2)  
     
     
     
     matrix%281%2C3%2C+matrix%282%2C1%2C+%22%22%2C+x%5E%281%2F2%29%29%2C+%22=%22%2C+e%5E3%29 ----------- Converting to EXPONENTIAL form 
     matrix%281%2C3%2C+%28x%5E%281%2F2%29%29%5E2%2C+%22=%22%2C+%28e%5E3%29%5E2%29 ---- Squaring both sides