SOLUTION: x=4sin(t), y=3cos(t), 0 <= t <= 2pi What is the initial point of this curve?

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Question 1095404: x=4sin(t), y=3cos(t), 0 <= t <= 2pi
What is the initial point of this curve?
Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!

The "initial point" of a curve is at the beginning of the interval defined for the parameter. With the parameter t going from 0 to 2pi, the initial point is determined by the x and y values when t=0.
x+=+4sin%28t%29+=+4sin%280%29+=+4%280%29+=+0
y+=+3cos%28t%29+=+3cos%280%29+=+3%281%29+=+3

The initial point is (x,y) = (0,3).