SOLUTION: Hi, can you please help me solve these equations to find x: 1) 3^2x - 5 x 3^x + 6 = 0 2) 3^2x - 5 x 3^x + 6 = 0 Thankyou so much in advance :)

Algebra ->  Exponents -> SOLUTION: Hi, can you please help me solve these equations to find x: 1) 3^2x - 5 x 3^x + 6 = 0 2) 3^2x - 5 x 3^x + 6 = 0 Thankyou so much in advance :)      Log On


   

Question 1095263: Hi, can you please help me solve these equations to find x:
1) 3^2x - 5 x 3^x + 6 = 0
2) 3^2x - 5 x 3^x + 6 = 0
Thankyou so much in advance :)
Answer by ikleyn(52831) About Me  (Show Source):
You can put this solution on YOUR website!
.
3%5E%282x%29+-5%2A3%5Ex+%2B+6 = 0  ====>  factor left side =====>


%283%5Ex-3%29%2A%283%5Ex-2%29 = 0  ====>


There are two solutions:


    1)  3%5Ex+-+3 = 0  ====>  3%5Ex = 3   ====>  x = 1;

and

    2)  3%5Ex-2 = 0  ====>  3%5Ex = 2  ====>  x = log%283%2C%282%29%29.


Answer.  x = 1  or/and  x = log%283%2C%282%29%29.

Solved.

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What I did not understand is: for what reason did you post two identical equations ??