SOLUTION: Susan invests 2 times as much money at 12% as she does at 9%. If her total interest after 1 year is $1320, how much does she have invested at each rate? Susan invests $ ( )

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Question 1095261: Susan invests 2 times as much money at 12% as she does at 9%. If her total interest after
1 year is $1320, how much does she have invested at each rate?
Susan invests $ ( ) at 9% and $ ( ) at 12%.

Found 2 solutions by addingup, josmiceli:
Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
0.09x + 0.12(2x) = 1320
0.09x + 0.24x = 1320
0.33x = 1320
x = 4000 this is the amount invested at 9%
2x = 2(4000) = 8000 this is the amount invested at 12%

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Assuming simple interest:
+I%5B1%5D+=+P%2Ar%5B1%5D%2At+
+r%5B1%5D+=+.09+
+t+=+1+
+I%5B1%5D+=+.09P+
---------------------
+I%5B2%5D+=+2P%2Ar%5B2%5D%2At+
+r%5B2%5D+=+.12+
+t+=+1+
+I%5B2%5D+=+.24P+
---------------------
given:
+i%5B1%5D+%2B+I%5B2%5D+=+1320+
+.09P+%2B+.24P+=+1320+
+.33P+=+1320+
+P+=+4000+
and
+2P+=+8000+
-----------------
She invests $4,000 @ 9%
She invests $8,000 @ 12%
--------------------------
check:
+I%5B1%5D+=+.09P+
+I%5B1%5D+=+.09%2A4000+
+I%5B1%5D+=+360+
and
+I%5B2%5D+=+.24P+
+I%5B2%5D+=+.24%2A4000+
+I%5B2%5D+=+960+
---------------------
+I%5B1%5D+%2B+I%5B2%5D+=+1320+
+360+%2B+960+=+1320+
+1320+=+1320+
OK