SOLUTION: find three consecutive odd integers such that 19 more than the first is 67 less than three times the last.
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Question 1095225
:
find three consecutive odd integers such that 19 more than the first is 67 less than three times the last.
Answer by
josmiceli(19441)
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Let the consecutive odd integers be:
,
, and
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and
and
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The numbers are 37, 39, and 41
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check:
OK
