SOLUTION: Can someone help? How to find the term containing x^15y^14 in the expansion of (2x^3+3y^2)^12 Thank you.

The formula to find a SPECIFIC term in a BINOMIAL expansion is: 
, where r = term number
 ------ Substituting  for a,  for b, and 12 for n


 
When the above binomial is expanded, the term that contains  is the one in which:


Thus, 15 = 3(13 – r) ------ Bases are equivalent, and so are the exponents
3(5) = 3(13 – r)
5 = 13 – r
5 – 13 = - r
- 8 = - r
r, or term number where  occurs = 

**Note: If calculated, the 8th term will also contain .