SOLUTION: A grocer bought some oranges at a cost of 3 for 48 cents, and then twice as many at a cost of 4 for 58 cents. In order to make a profit of 25%, he must sell them all at a price of

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: A grocer bought some oranges at a cost of 3 for 48 cents, and then twice as many at a cost of 4 for 58 cents. In order to make a profit of 25%, he must sell them all at a price of       Log On

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Question 1095004: A grocer bought some oranges at a cost of 3 for 48 cents, and then twice as many at a cost of 4 for 58 cents. In order to make a profit of 25%, he must sell them all at a price of 4 for m cents. The value of m, in cents, is
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +k+ = the number of oranges bought @ 3 for 48 cents
+%28+48%2F3+%29%2Ak+=+16k+ is the amount spent
+2k+ = the number bought @ 4 for 58 cents
+%28+58%2F4+%29%2A2k+=+29k+ is the amount spent
+16k+%2B+29k+=+45k+ is the total spent
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+45k+%2B+.25%2A45k+=+%28+m%2F4+%29%2A%28+k+%2B+2k+%29+
+1.25%2A45k+=+3k%2A%28+m%2F4+%29+
+5%2A45k+=+3k%2Am+
Divide both sides by +k+
+225+=+3m+
+m+=+75+
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check:
+1.25%2A45k+=+3k%2A%28m%2F4%29+
+225+=+3m+
+m+=+75+
OK
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