SOLUTION: If m < EBC = 31a-2 and m < EBH = 4a+45, find m < HBC.
Picture of the equation: https://i.imgur.com/ou44uBB.png
I tried solving for 31a-2=4a+45 and got 47/27. My teacher gave
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-> SOLUTION: If m < EBC = 31a-2 and m < EBH = 4a+45, find m < HBC.
Picture of the equation: https://i.imgur.com/ou44uBB.png
I tried solving for 31a-2=4a+45 and got 47/27. My teacher gave
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Question 1094979: If m < EBC = 31a-2 and m < EBH = 4a+45, find m < HBC.
Picture of the equation: https://i.imgur.com/ou44uBB.png
I tried solving for 31a-2=4a+45 and got 47/27. My teacher gave a poor example and didn't really try explaining it to me. What am I supposed to do with the fraction part of the equation to solve for angle HBC? Answer by MathTherapy(10552) (Show Source):
You can put this solution on YOUR website!
If m < EBC = 31a-2 and m < EBH = 4a+45, find m < HBC.
Picture of the equation: https://i.imgur.com/ou44uBB.png
I tried solving for 31a-2=4a+45 and got 47/27. My teacher gave a poor example and didn't really try explaining it to me. What am I supposed to do with the fraction part of the equation to solve for angle HBC?
You set ∡EBC = ∡EBH, but the 2 angles are not equal, so you CANNOT do that. And, as far as I see, none of the angles are equal.
Unless other info is given, ∡HBC will not have a NUMERICAL value.
∡EBC = 31a – 2 ∡EBH = 4a + 45
∡EBH + ∡HBC = ∡EBC
4a + 45 + ∡HBC = 31a - 2 -------- Substituting 4a + 45 for ∡EBH, and 31a – 2 for ∡EBC
∡HBC = 31a – 2 – 4a – 45
∡HBC =
