SOLUTION: could you please help me solve the equation for θ [0,2pi] 2 sin^2 θ − 1 = 0 there is a hint given that says that I may need to factor or use an identity but I d

Algebra ->  Trigonometry-basics -> SOLUTION: could you please help me solve the equation for θ [0,2pi] 2 sin^2 θ − 1 = 0 there is a hint given that says that I may need to factor or use an identity but I d      Log On


   

Question 1094868: could you please help me solve the equation for θ [0,2pi]
2 sin^2 θ − 1 = 0
there is a hint given that says that I may need to factor or use an identity but I don't not know how to get rid of the sin^2 because then I am left with sinθ= sqrt(-1/2)
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
2sin^2 - 1 = 0
2sin^2 = 1
sin^2 = 1/2
sin = sqrt(2)/2
theta = 45, 135 degs
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sin = -sqrt(2)/2
theta = 225, 315 degs
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Theta = pi/4, 3pi/4, 5pi/4, 7pi/4