SOLUTION: Determine whether the following system of equations are consistent, independent and inconsistent
t-u+2v-3w=9
4t+11v-10w=46
3t-u+8v-6w=27.
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-> SOLUTION: Determine whether the following system of equations are consistent, independent and inconsistent
t-u+2v-3w=9
4t+11v-10w=46
3t-u+8v-6w=27.
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Question 1094810: Determine whether the following system of equations are consistent, independent and inconsistent
t-u+2v-3w=9
4t+11v-10w=46
3t-u+8v-6w=27. Answer by ikleyn(52887) (Show Source):
Your matrix
X1 X2 X3 X4 b
1 1 -1 2 -3 9
2 4 0 11 -10 46
3 3 -1 8 -6 27
Find the pivot in the 1st column in the 1st row
X1 X2 X3 X4 b
1 1 -1 2 -3 9
2 4 0 11 -10 46
3 3 -1 8 -6 27
Multiply the 1st row by 4
X1 X2 X3 X4 b
1 4 -4 8 -12 36
2 4 0 11 -10 46
3 3 -1 8 -6 27
Subtract the 1st row from the 2nd row and restore it
X1 X2 X3 X4 b
1 1 -1 2 -3 9
2 0 4 3 2 10
3 3 -1 8 -6 27
Multiply the 1st row by 3
X1 X2 X3 X4 b
1 3 -3 6 -9 27
2 0 4 3 2 10
3 3 -1 8 -6 27
Subtract the 1st row from the 3rd row and restore it
X1 X2 X3 X4 b
1 1 -1 2 -3 9
2 0 4 3 2 10
3 0 2 2 3 0
Make the pivot in the 2nd column by dividing the 2nd row by 4
X1 X2 X3 X4 b
1 1 -1 2 -3 9
2 0 1 3/4 1/2 5/2
3 0 2 2 3 0
Multiply the 2nd row by -1
X1 X2 X3 X4 b
1 1 -1 2 -3 9
2 0 -1 -3/4 -1/2 -5/2
3 0 2 2 3 0
Subtract the 2nd row from the 1st row and restore it
X1 X2 X3 X4 b
1 1 0 11/4 -5/2 23/2
2 0 1 3/4 1/2 5/2
3 0 2 2 3 0
Multiply the 2nd row by 2
X1 X2 X3 X4 b
1 1 0 11/4 -5/2 23/2
2 0 2 3/2 1 5
3 0 2 2 3 0
Subtract the 2nd row from the 3rd row and restore it
X1 X2 X3 X4 b
1 1 0 11/4 -5/2 23/2
2 0 1 3/4 1/2 5/2
3 0 0 1/2 2 -5
Make the pivot in the 3rd column by dividing the 3rd row by 1/2
X1 X2 X3 X4 b
1 1 0 11/4 -5/2 23/2
2 0 1 3/4 1/2 5/2
3 0 0 1 4 -10
Multiply the 3rd row by 11/4
X1 X2 X3 X4 b
1 1 0 11/4 -5/2 23/2
2 0 1 3/4 1/2 5/2
3 0 0 11/4 11 -55/2
Subtract the 3rd row from the 1st row and restore it
X1 X2 X3 X4 b
1 1 0 0 -27/2 39
2 0 1 3/4 1/2 5/2
3 0 0 1 4 -10
Multiply the 3rd row by 3/4
X1 X2 X3 X4 b
1 1 0 0 -27/2 39
2 0 1 3/4 1/2 5/2
3 0 0 3/4 3 -15/2
Subtract the 3rd row from the 2nd row and restore it
X1 X2 X3 X4 b
1 1 0 0 -27/2 39
2 0 1 0 -5/2 10
3 0 0 1 4 -10
Solution set:
x1 = 39 + (27/2)x4
x2 = 10 + (5/2)x4
x3 = -10 - 4x4
x4 - free
Consistent and independent.
About the term "independent system of equations" see this Wikipedia article
https://en.wikipedia.org/wiki/Independent_equation
About the term "consistent/inconsistent system of equations" see this Wikipedia article
https://en.wikipedia.org/wiki/Consistent_and_inconsistent_equations