SOLUTION: What are all the real values of x which satisfy the equation: (x-7)(x^2+6x+4)=-(x-7)

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Question 1094793: What are all the real values of x which satisfy the equation: (x-7)(x^2+6x+4)=-(x-7)
Found 2 solutions by ultrakimidis1, MathTherapy:
Answer by ultrakimidis1(8) About Me  (Show Source):
You can put this solution on YOUR website!
(X-7)(X²+6X+4)=-(X-7)
divide through by (X-7)
X²+6X+4=-1
X²+6X+4+1=0
X²+6X+5=0
X=-1 OR X=-5 satisfy the equation

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

What are all the real values of x which satisfy the equation: (x-7)(x^2+6x+4)=-(x-7)