SOLUTION: A certain triangle has a perimeter of
3065 mi. The shortest side measures
71 mi less than the middle​ side, and the longest side measures
373 mi more than the middle si
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: A certain triangle has a perimeter of
3065 mi. The shortest side measures
71 mi less than the middle​ side, and the longest side measures
373 mi more than the middle si
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Question 1094711: A certain triangle has a perimeter of
3065 mi. The shortest side measures
71 mi less than the middle side, and the longest side measures
373 mi more than the middle side. Find the lengths of the three sides.
what is the length of short, middle and long sides? Answer by ikleyn(52781) (Show Source):
Let x be the length of the middle side (in mi units).
Then the length of the shortest side is x-71 mi,
and the length of the longest side is (x+373) mi.
The "perimeter equation" is
x + (x-71) + (x+373) = 3065.
Simplify and solve for x:
3x + 302 = 3065 ====> 3x = 2763 ====> x = = 921.
Middle side is of 921 mi long,
shortest side is 921-71 = 850 mi long,
longest side is 921+373 = 1294 mi long.
Check. You need to check that all three "triangle inequalities" are valid.
Please do it on your own.
