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Question 1094664: Find the center, vertices, and foci of the ellipse with equation x^2/400 + y^2/256 = 1.
Answer by ikleyn(52903)   (Show Source):
You can put this solution on YOUR website! .
Center is at (0,0).
Vertices (-20,0), (20,0), (0,16) and (0,-16).
Ellipse is wider than tall.
Linear eccentricity is c =  =  = 12.
Foci are at (-12,0) and (12,0).
See the lessons
- Ellipse definition, canonical equation, characteristic points and elements
- Standard equation of an ellipse
- Identify elements of an ellipse given by its standard equation
- Find the standard equation of an ellipse given by its elements
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lesson is the part of this online textbook under the topic
"Conic sections: Ellipses. Definition, major elements and properties. Solved problems".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.
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