SOLUTION: find three consecutive odd intergers such that the second is 20 less than 3 times the third intergers

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: find three consecutive odd intergers such that the second is 20 less than 3 times the third intergers       Log On


   

Question 1094651: find three consecutive odd intergers such that the second is 20 less than 3 times the third intergers
Found 3 solutions by josgarithmetic, MathTherapy, ikleyn:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
n, the second odd integer
n+2, the third odd integer

n=-20%2B3%28n%2B2%29

Answer by MathTherapy(10553) About Me  (Show Source):
You can put this solution on YOUR website!

find three consecutive odd intergers such that the second is 20 less than 3 times the third intergers 
Let 1st integer be F

Then others are: F + 2, and F + 4

We then get: F + 2 = 3(F + 4) - 20

F + 2 = 3F + 12 - 20

F - 3F = - 8 - 2

- 2F = - 10

F, or 1st integer = highlight_green%28matrix%281%2C3%2C+%28-+10%29%2F%28-+2%29%2C+%22=%22%2C+5%29%29

2nd and 3rd integers: highlight_green%28matrix%281%2C3%2C+%227%2C%22%2C+and%2C+9%29%29

Answer by ikleyn(52805) About Me  (Show Source):
You can put this solution on YOUR website!
.
find three consecutive odd intergers such that the second is 20 less than 3 times the third highlight%28cross%28intergers%29%29 integer.
~~~~~~~~~~~~~~~~~~~~~~~~~~

When I look in this problem, I have only one thought and only one question: 

    What the first number is doing in this problem
    and for what reason is it included to the condition ?