SOLUTION: A man has invested $18,000 in two parts. One part is invested at 8% and the remainder at 10%. The income from the 10% investment is $360 more than the income from the 8% investment

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: A man has invested $18,000 in two parts. One part is invested at 8% and the remainder at 10%. The income from the 10% investment is $360 more than the income from the 8% investment      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1094642: A man has invested $18,000 in two parts. One part is invested at 8% and the remainder at 10%. The income from the 10% investment is $360 more than the income from the 8% investment. How much does he invest at each rate?
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
a+b=18000
.10a=.08b+360