SOLUTION: Taylor has 85 cents in dimes and nickels in her pocket. The number of dimes is four more than the number of nickels. How many of each coin does she have?

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Taylor has 85 cents in dimes and nickels in her pocket. The number of dimes is four more than the number of nickels. How many of each coin does she have?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1094639: Taylor has 85 cents in dimes and nickels in her pocket. The number of dimes is four more than the number of nickels. How many of each coin does she have?
Found 2 solutions by josmiceli, josgarithmetic:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +n+ = number of nickels
Let +d+ = number of dimes
-----------------------------
(1) +5n+%2B+10d+=+85+
(2) +d+=+n+%2B+4+
----------------------------
Substitute (2) into (1)
(1) +5n+%2B+10%2A%28+n+%2B+4+%29+=+85+
(1) +5n+%2B+10n+%2B+40+=+85+
(1) +15n+=+45+
(1) +n+=+3+
and
(2) +d+=+n+%2B+4+
(2) +d+=+3+%2B+4+
(2) +d+=+7+
---------------------
There are 3 nickels and 7 dimes
-------------------------------
check:
(1) +5n+%2B+10d+=+85+
(1) +5%2A3+%2B+10%2A7+=+85+
(1) +15+%2B+70+=+85+
(1) +85+%2B+85+
OK

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
system%28d-n=4%2C5n%2B10d=85%29

system%28n%2B2d=17%2C-n%2Bd=4%29

highlight%28d=7%29---------------seven dimes
highlight%28n=3%29---------------three nickels