SOLUTION: If the arithmetic mean of two numbers a & b (0<a<b) is 6 and their geometric mean G and harmonic mean H satisfy the relation G^2 +3H=48. Then what is the value of (2a-b)?

Algebra ->  Sequences-and-series -> SOLUTION: If the arithmetic mean of two numbers a & b (0<a<b) is 6 and their geometric mean G and harmonic mean H satisfy the relation G^2 +3H=48. Then what is the value of (2a-b)?      Log On