SOLUTION: Points R(1, 3), S(–2, –1), and T(5, –1) are vertices of a parallelogram. Give the coordinates of three possible points of the other vertex.

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: Points R(1, 3), S(–2, –1), and T(5, –1) are vertices of a parallelogram. Give the coordinates of three possible points of the other vertex.       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1094441: Points R(1, 3), S(–2, –1), and T(5, –1) are vertices of a parallelogram. Give the coordinates of three possible points of the other vertex.

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Points S%28-2%2C-1%29 and T%285%2C-1%29 define a horizontal segment ST,
with a length of 5-%28-2%29=7 units.
units to the left of R%281%2C3%29 , at U,
or 7 units to the right of R%281%2C3%29 , at V.
with an x-coordinate of eitherx=1-7=-6 or x=1%2B7=8 ,
and of course the same y=3 as point R.
So, highlight%28U%28-6%2C3%29%29 and highlight%28V%288%2C3%29%29 are two of the possible locations of the fourth vertex.
Those two options give you parallelograms SURT and SRVT, shown below.
and
If ST is a diagonal, then RT and RS are sides,
R is above diagonal ST, and fourth vertex W is below the diagonal
with SW parallel to RT,
SW slanting down from S%28-2%2C-1%29 , just as RT slants down from R,
going y%5BR%5D-y%5BT%5D=3-%28-1%29=4 units down,
and x%5BT%5D-x%5BR%5D=5-1=4 units to the right.
That gives us y%5BW%5D=y%5BS%5D-4=-1-4=-5 ,
and x%5BW%5D=x%5BS%5D%2B4=-2%2B4=2 ,
and puts the fourth vertex at highlight%28W%282%2C-5%29%29 .
With W, you form parallelogram SWTR, shown below.