SOLUTION: If logax=4 and logay=5, use log laws to find the exact values of: loga(x^2y) loga(axy) loga(xy) I have no idea how to do these questions - i tried googling them and there

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: If logax=4 and logay=5, use log laws to find the exact values of: loga(x^2y) loga(axy) loga(xy) I have no idea how to do these questions - i tried googling them and there      Log On


   

Question 1094218: If logax=4 and logay=5, use log laws to find the exact values of:
loga(x^2y)
loga(axy)
loga(xy)
I have no idea how to do these questions - i tried googling them and there not in my textbook. any help would be greatly appreatiated. thankyou so much in advance.
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
+log%28a%2C%28x%29%29+=+4+
+log%28a%2C+%28y%29%29+=+5+
—
The two properties of logarithms needed to do these are:
+log%28%28m%2An%29%29+=+log%28%28m%29%29+%2B+log%28%28n%29%29+
and
+log%28%28m%5Ek%29%29+=+k%2Alog%28%28m%29%29+
—
Since you are given +log%28a%2C%28x%29%29+ and +log%28a%2C%28y%29%29+ you should try to rearrange the given expression in terms of these so that you can plug in the numbers:


I'll leave the 3rd one for you. It is very similar (simpler) than the 2nd one above.
Hope this helps.