SOLUTION: the cost of two chocolate bars and three cameral bars is $6.00 the cost of one chocolate bar is 0.50 less than twice the price of cameral bars find the price of each item.

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: the cost of two chocolate bars and three cameral bars is $6.00 the cost of one chocolate bar is 0.50 less than twice the price of cameral bars find the price of each item.      Log On


   

Question 1094193: the cost of two chocolate bars and three cameral bars is $6.00 the cost of one chocolate bar is 0.50 less than twice the price of cameral bars find the price of each item.
Answer by josgarithmetic(39616) About Me  (Show Source):
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The cost of two chocolate bars and three cameral bars is $6.00.
The cost of one chocolate bar is $0.50 less than twice the price of A cameral bar.
Find the price of each item.
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ASSIGN VARIABLES
x, price of chocolate bar
y, price of caramel bar ("cameral"?)

TRANSLATE DESCRIPTION INTO EQUATIONS
system%282x%2B3y=6%2Cx=2y-0.5%29

Solve the system any way you know or are expected.