SOLUTION: The length of a rectangle is 59 inches greater than twice the width. If the diagonal is 2 inches more than the​ length, find the dimensions of the rectangle.
x, 2x+59.
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x, 2x+59.
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Question 1094179: The length of a rectangle is 59 inches greater than twice the width. If the diagonal is 2 inches more than the length, find the dimensions of the rectangle.
x, 2x+59.
from the upper left corner to lower right is 2x+61 Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! If the width of the rectangle is x, then its' length is 2x+59. And the diagonal across the 2 lines is 2x+61. So:
x²+(2x+59)²=(2x+61)²
x²+4x²+236x+3481=4x²+244x+3721
x²-8x-240=0
(x+12)(x-20)=0
x=20 or -12
The sides are 20 and 99 inches in length.
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