SOLUTION: Suppose 12 men and 9 women went to the canal to pan for gold. If two people were chosen at random, what is the probability that one man and one woman were chosen? Round your answer
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-> SOLUTION: Suppose 12 men and 9 women went to the canal to pan for gold. If two people were chosen at random, what is the probability that one man and one woman were chosen? Round your answer
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Question 1094163: Suppose 12 men and 9 women went to the canal to pan for gold. If two people were chosen at random, what is the probability that one man and one woman were chosen? Round your answer to the nearest hundredth percent.
You can put this solution on YOUR website! We've a total of 21 people, (12 men and 9 women)
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Total ways of selecting 2 people of 21 = 21C2 = 420
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Total ways of selecting 1 man of 12 = 12C1 = 12
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Total ways of selecting 1 woman of 9 = 9C1 = 9
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If 1 man and 1 woman, then total ways = 12*9 = 108
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P(1m and 1w) = 108/420
Approx. = 0.26
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Your friend,
Francis.
