SOLUTION: In a sample of 1100 U.S.​ Adults, 198 dine out at a restaurant more than once per week. Two U.S. adults are selected at random from the population of all U.S. adults without
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-> SOLUTION: In a sample of 1100 U.S.​ Adults, 198 dine out at a restaurant more than once per week. Two U.S. adults are selected at random from the population of all U.S. adults without
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Question 1094137: In a sample of 1100 U.S. Adults, 198 dine out at a restaurant more than once per week. Two U.S. adults are selected at random from the population of all U.S. adults without replacement. Assuming the sample is representative of all U.S. adults, complete parts (a) through (d).
(a) Find the probability that both adults dine out more than once per week.
The probability that both adults dine out more than once per week is .
(Round to three decimal places as needed.)
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.
n(r) = 198
.
n(s) = 1100
.
Typically,
P(2 adults without replacement)
=
.
=
.
Probability will be approximately 0.032 to 3 d.p
.
.
.
Your friend,
Francis.
