SOLUTION: Walt rode his bike from home to the bicycle repair shop and then walked home. He averaged 18 km/h riding and 6 km/h walking. If his total travel time was one hour, how far is it to

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Walt rode his bike from home to the bicycle repair shop and then walked home. He averaged 18 km/h riding and 6 km/h walking. If his total travel time was one hour, how far is it to      Log On

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Question 1094064: Walt rode his bike from home to the bicycle repair shop and then walked home. He averaged 18 km/h riding and 6 km/h walking. If his total travel time was one hour, how far is it to the shop from Walt's home?
Answer by greenestamps(13208) About Me  (Show Source):
You can put this solution on YOUR website!

First a traditional solution using formal algebra....

Let the distance (in km) be d. Then the number of hours it took him to ride to the repair shop at 18 km/hr is d/18; the number of hours it took him to walk home at 6 km/hr is d/6. Since the total time was 1 hour,

d%2F18+%2B+d%2F6+=+1
d+%2B+3d+=+18
4d+=+18
d+=+4.5

The distance from his home to the repair shop was 4.5 km.

And now for a solution that is made easier by first doing some logical analysis....

His walking speed is 1/3 as fast as his riding speed. Since he traveled the same distance riding and walking, he spent 3 times as much time walking as he did riding. Since the total time was 1 hour, he rode for 1/4 hour and walked for 3/4 hour. Then you can find the distance to the repair shop using either the riding part of the trip...
18%2A%281%2F4%29+=+4.5
or the walking part...
6+%2A+%283%2F4%29+=+4.5