SOLUTION: A scuba diver, hired by an amusement park, collected $164 in nickels, dimes, and quarters at the bottom of a wishing well. There were 700 nickels, and 110 more quarters than dimes.

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: A scuba diver, hired by an amusement park, collected $164 in nickels, dimes, and quarters at the bottom of a wishing well. There were 700 nickels, and 110 more quarters than dimes.      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1094043: A scuba diver, hired by an amusement park, collected $164 in nickels, dimes, and quarters at the bottom of a wishing well. There were 700 nickels, and 110 more quarters than dimes. How many quarters and dimes were thrown into the wishing well?
Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!

First a solution using logical analysis to cut down on the amount of work required....

Start with the total of $164.
Subtract the value of the 700 nickels.
164+-+700%28.05%29+=+164-35+=+129
Subtract the "extra" 110 quarters (this will leave equal numbers of quarters and dimes).
129+-+110%28.25%29+=+129-27.50+=+101.50
The remaining amount is made up of equal numbers of quarters and dimes. Since one quarter and one dime together make 35 cents (0.35 dollars), divide the remaining dollar amount by 0.35 dollars to find the number of dimes.
101.50%2F0.35+=+290

The number of dimes is 290; so the number of quarters is 290+110 = 400.

Using formal algebra...

let d = # of dimes
then d+110 = # of quarters

We know the number of nickels is 700; and we know the total value of all the coins is 164. So (using cents instead of dollars to avoid using decimals...)
25%28d%2B110%29+%2B+10%28d%29+%2B+5%28700%29+=+16400
25d%2B2750+%2B+10d+%2B+3500+=+16400
35d+=+10150
d+=+10150%2F35+=+290