Question 1094039: How many gallons of a 80% antifreeze solution must be mixed with 60 gallons of 30% antifreeze to get a mixture that is 70% antifreeze? Found 4 solutions by Alan3354, josmiceli, ikleyn, greenestamps:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! How many gallons of a 80% antifreeze solution must be mixed with 60 gallons of 30% antifreeze to get a mixture that is 70% antifreeze?
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Do it like this one:
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How many liters of a 75% antifreeze solution must be mixed with 50 liters of 30% antifreeze to get a mixture that is 65% antifreeze?
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Add L liters.
50*30 + L*75 = (50+L)*65
Solve for L
You can put this solution on YOUR website! Let = gallons of 80% antifreeze needed
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240 gallons of 80% solution are needed
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check:
OK
You can put this solution on YOUR website! If you want to learn a faster way to solve mixture problems, look at this method for solving your problem.
(1) The mixture is 70%; the ingredients are 80% and 30%.
(2) The 70% is 4 times as close to the 80% as it is to the 30%: ; ;
(3) Since the mixture percentage is 4 times as close to 80 as it is to 30, the amount of the 80% ingredient must be 4 times the amount of the 30% ingredient.
That's it. There are 60 gallons of the 30% antifreeze, so the number of gallons of 80% antifreeze must be 4*60 = 240.
