SOLUTION: The larger of two numbers is six less than twice the smaller number. If the sum of the number is 42, find the numbers

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Question 1093940: The larger of two numbers is six less than twice the smaller number. If the sum of the number is 42, find the numbers

Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
x = larger number
y = smaller number

x = 2y - 6
x + y = 42

Use substitution.

2y - 6 + y = 42
3y - 6 = 42
3y = 48
y = 16

The numbers are 26 and 16.