SOLUTION: Jack is 44 times as old as Lacy 9 years from now the sum of their ages will be 88 . How old are they now

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Question 1093597: Jack is 44 times as old as Lacy 9
years from now the sum of their ages will be 88
. How old are they now

Found 3 solutions by Alan3354, ikleyn, josgarithmetic:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Jack is 44 times as old as Lacy
9 years from now the sum of their ages will be 88. How old are they now
-------------
J = 44L
J + L = 70 now.
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44L + L = 70
L = 70/44 = 35/22 years
J = 70

Answer by ikleyn(52804) About Me  (Show Source):
You can put this solution on YOUR website!
.
In age word problems, the solutions ALWAYS are assumed to be integer numbers expressing the age of participants in years.

If it is not so, the problems and their conditions are qualified as DEFECTIVE.


Without any further discussions.



Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Jack now, 44x
Lacy now, x

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9 years from now the sum of their ages will be 88.
----------------------------------------------------

%2844x%2B9%29%2B%28x%2B9%29=88
-
.
.
Lacy, x=1%265%2F9
Jack, 4x=68%264%2F9