SOLUTION: The sum of three consecutive odd integers is 32 more than the smallest. What are the intergers? Here's what I have: n+(n+2)+(n+4)= n+32

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: The sum of three consecutive odd integers is 32 more than the smallest. What are the intergers? Here's what I have: n+(n+2)+(n+4)= n+32      Log On


   

Question 1093514: The sum of three consecutive odd integers is 32 more than the smallest. What are the intergers?
Here's what I have:
n+(n+2)+(n+4)= n+32
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
Your equation is good.
n%2Bn%2B2%2Bn%2B4=n%2B32
3n%2B6=n%2B32
2n=32-6=26
n=13 and the next two are system%2815%2C+and%2C+17%29.