SOLUTION: Find two consecutive odd integers that 41 more than the lesser is four times the greater

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Question 1093483: Find two consecutive odd integers that 41 more than the lesser is four times the greater
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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Find two consecutive odd integers
n & (n+2)
that 41 more than the lesser is four times the greater
n + 41 = 4(n+2)
n + 41 = 4n + 8
41 - 8 = 4n - n
33 = 3n
n = 33/3
n = 11
:
the two consecutive odd integers, 11 & 13
:
:
Check this
11 + 41 = 4(13)
52 = 52