SOLUTION: If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation h = -16t^2+vt+s, wh
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-> SOLUTION: If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation h = -16t^2+vt+s, wh
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Question 1093456: If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation h = -16t^2+vt+s, where h is in feet. If the object is propelled from a height of 12 feet with an initial velocity of 64 feet per second, it's height h is given by the equation h = -16t^2+64t+12. After how many seconds is the height 72 feet? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! If the object is propelled from a height of 12 feet with an initial velocity of 64 feet per second, it's [sic] height h is given by the equation h = -16t^2+64t+12. After how many seconds is the height 72 feet?
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h = -16t^2+64t+12 = 72
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-16t^2+64t+12 = 72
Solve for t. What's the big deal?
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it's = it is
