SOLUTION: Your 1,360 kg car accelerates at 2.5 m/s^2 for 4 s. What is the net force applied to produce this acceleration? What is the car;s final velocity? (mi/hr) How far does the c

Algebra ->  Finance -> SOLUTION: Your 1,360 kg car accelerates at 2.5 m/s^2 for 4 s. What is the net force applied to produce this acceleration? What is the car;s final velocity? (mi/hr) How far does the c      Log On


   

Question 1093453: Your 1,360 kg car accelerates at 2.5 m/s^2 for 4 s.
What is the net force applied to produce this acceleration?
What is the car;s final velocity? (mi/hr)
How far does the car move during the acceleration? (in m and ft)
Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.
1.   Your 1,360 kg car accelerates at 2.5 m/s^2 for 4 s. 
     What is the net force applied to produce this acceleration?


     Net force = m*a, the mass multiplied by the acceleration (second Newton law) = 

                 1360 * 2.5 Newtons.  Calculate it on your own.



2.  What is the car's final velocity? (mi/hr)

    Final velocity  V = at = acceleration multiplied by time = 2.5 * 4 m/s.

    Calculate it on your own.  Then convert to miles per hour.

    1 mile = 1609.34 meters.  1 hour = 3600 seconds.



3.  How far does the car move during the acceleration? (in m and ft)

    The distance the uniformly accelerated body travels from the rest for the time t is 

    S = %28at%5E2%29%2F2 = %282.5%2A4%5E2%29%2F2 m/s.

    Calculate it on your own.