SOLUTION: An open box is to be constructed from a square piece of sheet metal by removing a square of side 55 feet from each corner and turning up the edges. ​ (See the figure on the&#

Algebra ->  Trigonometry-basics -> SOLUTION: An open box is to be constructed from a square piece of sheet metal by removing a square of side 55 feet from each corner and turning up the edges. ​ (See the figure on the&#      Log On


   



Question 1093433: An open box is to be constructed from a square piece of sheet metal by removing a square of side 55 feet from each corner and turning up the edges. ​ (See the figure on the​ right.) If the box is to hold 605605 cubic​ feet, what should be the dimensions of the sheet​ metal?
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!

Let x be the side length of the square box that is being constructed. Since squares of length 55 feet are cut out of each corner of the original piece of sheet metal, the side length of the original piece of metal is x+110.

The volume of the box, given as 605605 cubic feet, is 55x^2. So

55x%5E2+=+605605+=+605%2A1001+=+55%2A11%2A7%2A11%2A13
x%5E2+=+11%2A11%2A7%2A13
x+=+11%2Asqrt%2891%29

So the length of the side of the original piece of metal is

11%2Asqrt%2891%29%2B110