SOLUTION: (3+i)(5-i)

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: (3+i)(5-i)       Log On


   

Question 1093393: (3+i)(5-i)
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
(3+i)(5-i)
--------------
Same as any 2 binomials.
= 15 + 2i - i^2
i^2 = -1
--> 15 + 2i + 1
= 16 + 2i